26th lottery numbers
26th lottery numbers

Math question about possibilities – the lottery?
If there is a drawing of 36 numbers, the ball is going to be three numbers drawn. If I take 3 numbers What is the possibility of having two of the number that matches the draw for the lottery pick? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
assuming that the balls are not placed back in the lottery and not allowed to choose the same number more than once, the first selection the possibility of acquiring any of their number is 3 / 36 of the second inserting the possibility of acquiring other two numbers is 2 / 35 selection last time you do not have to get your third issue and that it is only asked to have two of their numbers to the possibility of getting the desired number is 33/34 (you can not have any 3 balls), so as the possibilities are related to multiply the three probabilities together: 3 / 36 * 2 / 35 * 33/34 = 11/2380 STILL get lost in the details small, the order of selection if our first number, the number of seconds or even not wanted to come to our number does not matter what we find possible combinations: 1) the number, unwanted, 2) number, number, desired number 3) the desired number, number, number, there are 3 combos 3 * 11/2380 = 0.013865546 or 1.39%
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